How do you find the middle column of an array in general?
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array = [0 1 2 3 4 3 2 1 0; 0 1 2 3 4 3 2 1 0; 0 1 2 3 4 3 2 1 0;0 1 2 3 4 3 2 1 0];
%--opt 5 - Set the middle column of array2D equal to zero. If there is an
% even number of columns, set the both of the middle columns to zero. The
% floor and ceil functions are useful for this.
function [array2D] = filterAndPlot(change, opt, array2D)
if opt == 5
columnMiddle = array2D(ceil(numel(array2D) / 2.0 ))
???
So I thought you have to take the Array and divide by two, then find the numel of that and then ceil of that. Then I took the array of that and that stores the value of the element in the middle of the array. Is there a way to take that value and get the column out of that?
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Image Analyst
2019-4-8
Hint: use rem() to determine if the number of columns divided by 2 is an even or odd number. Then use an if statement to carry out the assignment of column(s) to zero.
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Image Analyst
2019-4-8
No.
Plus, I don't know the point of opt5. That doesn't seem necessary at all given what you've shown.
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