Data representation in a specific format

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Saugata Bose
Saugata Bose 2019-4-28
评论： Walter Roberson 2019-4-29
Hi
I am working on a large data set which I need to convert in a specific format for further processing. I am looking for your advice in this regard.
Sample data
A=[0.99 -0.99
1 -1
0.55 -0.55]
Sample output:
val(:,:,1,1)=0.99
val(:,:,2,1)=-0.99
val(:,:,1,2)=1
val(:,:,2,2)=-1
val(:,:,1,3)=0.55
val(:,:,2,3)=-0.55
During working on this, I found a code inside a cnn toolbox of matlab r2018b
function dummifiedOut = dummify(categoricalIn)
% iDummify Convert a categorical input into a dummified output.
%
% dummifiedOut(1,1,i,j)=1 if observation j is in class i, and zero
% otherwise. Therefore, dummifiedOut will be of size [1, 1, K, N],
% where K is the number of categories and N is the number of
% observation in categoricalIn.
% Copyright 2015-2016 The MathWorks, Inc.
numObservations = numel(categoricalIn);
numCategories = numel(categories(categoricalIn));
dummifiedSize = [1, 1, numCategories, numObservations];
dummifiedOut = zeros(dummifiedSize);
categoricalIn = iMakeHorizontal( categoricalIn );
idx = sub2ind(dummifiedSize(3:4), int32(categoricalIn), 1:numObservations);
dummifiedOut(idx) = 1;
end
function vec = iMakeHorizontal( vec )
vec = reshape( vec, 1, numel( vec ) );
end
Can we modify this block of code in such a way to produce the sample output?
I am looking for your advice.
thanks,
  2 个评论
Walter Roberson
Walter Roberson 2019-4-28
You write to the same location multiple times.
Are your two values always exact negatives of each other?
Saugata Bose
Saugata Bose 2019-4-28
walter hi
most of the time, data appears exact opposite of the first one.
thanks,

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采纳的回答

Walter Roberson
Walter Roberson 2019-4-28
val = repmat(permute(A, [4 3 2 1]), num_rows, num_cols, 1, 1);
where num_rows is the number of rows you want for val(:,:,1,1) and num_cols is the number of columns you want for val(:,:,1,1)
  2 个评论
Saugata Bose
Saugata Bose 2019-4-29
@Walter Roberson
thanks for ur suggestion. Though I understand how this code block works yet, I need to understand if I am looking for such a following output, what changes the code block may demand? Could you please highlight this issue?
Sample output:
val(:,:,1,1)=0.99
val(:,:,2,1)=-0.99
val(:,:,3,1)=0
val(:,:,4,1)=0
val(:,:,1,2)=1
val(:,:,2,2)=-1
val(:,:,3,2)=0
val(:,:,4,2)=0
val(:,:,1,3)=0.55
val(:,:,2,3)=-0.55
val(:,:,3,3)=0
val(:,:,4,3)=0
Walter Roberson
Walter Roberson 2019-4-29
A = [0.99 -0.99 0 0
1 -1 0 0
0.55 -0.55 0 0
]
together with the code I posted.

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