Nested Loop Script (Triangle)

Question

Juan Zegarra 2019-4-28

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/459025-nested-loop-script-triangle

编辑： Sulaymon Eshkabilov 2019-5-6

Write a nested llop script that will print the following pattern, printing one number or character at a time starting at 1 and using the numbers 0 through 9 Screen Shot 2019-04-28 at 1.24.24 PM.png

Screen Shot 2019-04-28 at 1.24.24 PM.png

3 个评论
显示 1更早的评论隐藏 1更早的评论

Juan Zegarra 2019-4-28

在 MATLAB Online 中打开

This but im not sure what to print or how to do it for the first one.

for n=1:5
    for s=1:n
        fprintf('')
    end
    fprintf('\n')
end

Cedric 2019-4-28

编辑：Cedric 2019-4-28

在 MATLAB Online 中打开

It is a good start, you can try to display a charater followed by a space, just to make sure that your nested loops operate as desired:

for n = 1 : 5
    for m = 1 : n
        fprintf('A ') ;
    end
    fprintf('\n') ;
end

which outputs:

A 
A A 
A A A 
A A A A 
A A A A A

It looks like it is working. Now you solved one part of the problem, and there are many ways to solve the rest.

What happens if you keep incrementing some variable within the inner loop?

s = 1 ;
for n = 1 : 5
    for m = 1 : n
        fprintf('A ') ;  % What about displaying the value of s instead of 'A '?
        s = s + 1 ;
    end
    fprintf('\n') ;
end

Are you able to print the value of s instead of this character A? Maybe then you'll want to read about the modulo operation.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Sulaymon Eshkabilov 2019-5-6

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/459025-nested-loop-script-triangle#answer_373708

编辑：Sulaymon Eshkabilov 2019-5-6

在 MATLAB Online 中打开

Here is the complete answer to all parts of the assignment:

%%

clearvars; clc
%% Part 1.
k=1;
for ii = 1 : 5
    for jj = 1 : ii
        if k >10
            k=k-10;
            fprintf(num2str(k));
        else
        fprintf(num2str(k)) ;
        end
        k = k+1;
    end
    fprintf('\n') ;
end
%% Part 2
k = 65 ;
for ii = 1 : 5
    for jj = 1 : ii
        fprintf(char(k)) ;  
        k = k + 1 ;
    end
    fprintf('\n') ;
end
%% Part 3. Numbers
k=5;
for ii = 1 : 5
    for jj = 1 : ii
        if k >10
            k=k-10;
            fprintf(num2str(k));
        else
        fprintf(num2str(k)) ;
        end
        k = k+1;
    end
    fprintf('\n') ;
end
%% Part 3. Letters
k = 68 ;
for ii = 1 : 5
    for jj = 1 : ii
         fprintf(char(k) ) ;  
       k = k + 1 ;
    end
    fprintf('\n') ;
end