Populate structure array efficiently

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Anon
Anon 2012-8-17
Hi,
I am wondering if this question is too simple and if I am missing something important. How do I efficiently populate a structure array such that
A = 6:10;
and the resulting structure array is
S(1).A = 6;
S(2).A = 7;
...
S(5).A = 10;
Using a loop S is fairly easy to obtain, but there are probably much more efficient ways to do so.
Regards, Anon

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-8-17
S = struct('A',num2cell(A))

更多回答（1 个）

Walter Roberson
Walter Roberson 2012-8-17
It can be done, but it is not pretty.
S = struct( 'A', num2cell(6:10) )

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