Quadratic equation & Minus B

10 次查看（过去 30 天）
Fergal Ahern
Fergal Ahern 2019-5-15
回答： Pavi thra 2020-10-28
How do I solve the quadratic equation ax^2+bx+c=0 using the minus b formula, x=-b+- sqrt b^2-4ac/2a on MATLAB
Thank you
  3 个评论
显示 1更早的评论
Fergal Ahern
Fergal Ahern 2019-5-15
编辑：Fergal Ahern 2019-5-15
Geoff - The program must read in coefficients a,b and c from the keyboard and then calculate the roots of the equation. Do you know how I would verify that real roots are generated?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

kirti singh
kirti singh 2019-5-16
The following example code snippet works for accepting the coefficients a,b and c and calculating the roots and finding if they are real or not:
a1 = 'Enter value of a ';
a = input(a1)
b1= 'Enter value of b ';
b = input(b1)
c1= 'Enter value of c ';
c = input(c1)
x1 = (-b + sqrt(b^2 - (4 * a * c))) / (2 * a);
x2 = (-b - sqrt(b^2 - (4 * a * c))) / (2 * a);
t1=isreal(x1);
t2=isreal(x2);
  1 个评论
James Tursa
James Tursa 2019-5-16
Please don't post complete solutions to homework problems.

请先登录，再进行评论。

更多回答（1 个）

Pavi thra
Pavi thra 2020-10-28
a1 = 'Enter value of a ';
a = input(a1)
b1= 'Enter value of b ';
b = input(b1)
c1= 'Enter value of c ';
c = input(c1)
x1 = (-b + sqrt(b^2 - (4 * a * c))) / (2 * a);
x2 = (-b - sqrt(b^2 - (4 * a * c))) / (2 * a);
t1=isreal(x1);
t2=isreal(x2);

类别

在 Help Center 和 File Exchange 中查找有关 Measurements and Spatial Audio 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by