How to obtain the minimum values of an array?

1 次查看(过去 30 天)
I'm trying to get the minimum values of three vectors. Assuming that the length of the vectors is 1x4, I need to get 4 minimums. Also one of the vectors has as values a constant. I'm attaching the code. The important part is on lines 12 to 15.
function [x_t,Re,eta_c,C_f] = CXAPWING(b,b_slats,x_thickness,x_camber,M)
%%% Коэффициент профильного сопротивления крыла
h_polish = 1e-6; %micro
V = M*299.45;
Re = V*b/3.5232e-5;
F1 = 1.3+0.6*M*(1-0.25*M^2);
hbRe = h_polish*V/3.5232e-5;
F2 = log10(abs(hbRe-1));
F3 = (2.2-0.08*M^2)/(1+0.312*M);
n = 5+F1*(1-(F2/F3)^2)^0.5;
x_t_1 = 10^n/Re;
x_t_2 = sqrt(x_thickness*x_camber);
x_t_3 = b_slats/b;
x_t = min([x_t_1 x_t_2 x_t_3]);
if Re < 4.85e5
C_f = 1.328/sqrt(Re);
elseif Re > 3e7
C_f = 0.455/(log10(Re))^2.58;
else
C_f = (0.455./log10(Re).^2.58).*((1-x_t+(40*x_t^0.625)/Re.^0.375).^0.8)';
end
% nc_xt = [1.4072 1.3722 1.3536 1.3103 1.2557; 0 0.1 0.2 0.3 0.4]; % 0.11
nc_xt = [1.3323 1.3063 1.2917 1.2552 1.2115; 0 0.1 0.2 0.3 0.4]; %0.09
if x_t > 0 && x_t < 0.1
eta_c = INTERPOLATION(nc_xt(2,1),nc_xt(1,1),nc_xt(2,2),nc_xt(1,2),x_t);
elseif x_t > 0.1 && x_t < 0.2
eta_c = INTERPOLATION(nc_xt(2,2),nc_xt(1,2),nc_xt(2,3),nc_xt(1,3),x_t);
elseif x_t > 0.2 && x_t < 0.3
eta_c = INTERPOLATION(nc_xt(2,3),nc_xt(1,3),nc_xt(2,4),nc_xt(1,4),x_t);
else x_t > 0.3 && x_t < 0.4
eta_c = INTERPOLATION(nc_xt(2,4),nc_xt(1,4),nc_xt(2,5),nc_xt(1,5),x_t);
end
end

采纳的回答

madhan ravi
madhan ravi 2019-6-8
Have a look at mink() else use sort() and pick the first four values if you’re using older version.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Shifting and Sorting Matrices 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by