Hey all,
I know what I am asking is wrong, but I have to slove it at any cost.
I have sOme materials .1 2 3 4 5 6 7 8 9 10;
Now 1 and 2 are in series 1--2
2 and 3 are in series 2--3
3 and 4 are in series 3 --4
1 and 5 are in parallel =
8 and 5 are in series 8-5
8 and 6 are in parallel =
6 and 7 are in series 6-7
5 and 9 are in Series 5 - 9
9 and 10 are in series 9 -10
9 are 2 are in parallel =
10 and 3 are in parallel =
Now I need to build separate function file to let the slover knows which one is in parallel or series with other element.
My code is like this:
classdef Connection
enumeration
Series, Parallel
end
end
function [C] = find_Connection(i)
[Lambda, A, B, D, M, A1,M_S, M_P] = Matrix_surendra13;
C = 0;
if (find(M_S == i))
C = Connection.Series;
elseif (find(M_P == i))
C = Connection.Parallel;
end
function Slover
[Lambda, A, B, D, M, A1,M_S, M_P] = Matrix_surendra13;
for i = 1:Size(A,1)
for j = 1:size(A,2)
C1 = find_Connection(i);
C2 = find_Connection(j);
if (C1 == Connection.Series && C2 == Connection.Series)
LA = A(i,j)*B(i)*D(j)*Lambda(j);
elseif (C1 ==Connection.Parallel && C2 == Connection.Parallel)
LB = A(i,j)*Lambda(i)*Lambda(j);
end
So the problem is each material has two possiblities either Series or Parallel with others. If I use my code it doesn't work.
For an example,
i = 1; j = 1;
Material 1 is in Series with 2 and in Parallel with 5, when the solver enter the function file find_Connection(i) it will automatically take Series statement since first condition will be fulfilled. This is fine for 1 and 2. LA will be computed.
But when i = 1 and j = 5; in parallel
slover sholud take LB, but it will compute LB bcoz both i = 1 and i = 5 are there in series vector file as well as in parallel vector file, so first condtion in the find_Connection file will be fulfuilled, so solver will not check second one.
I think that I gave the proper explanation.
Kindly as for the more detail if it is not clear.
any suggestions and answers are most welcomed.
Thanks in Advance.
