Formatted string plus list of numbers using sprintf
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I would like to display comma-separated records like the following,
Record1,2,8,3,5,2,6,3,7,7,7
Here's my attempt, but is there a less clunky way?
% Make the record label string
iRecord = 1;
strLabel = ['Record' num2str(iRecord)];
% Make the number vector
numberList = round(rand(1,10)*10);
% Turn number vector into a string
numberListIntoString = sprintf('%d,', numberList);
% Remove comma at end
numberListIntoString = numberListIntoString(1:(end-1));
% Display the result
disp([strLabel ',' numberListIntoString])
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采纳的回答
Adam Danz
2019-6-18
numberList = round(rand(1,10)*10);
s = ['Record',regexprep(num2str([1,numberList]),' +',',')];
3 个评论
Adam Danz
2019-6-18
num2str([1,numberList])
That line adds more than 1 space between each number. The ' +' in the regular expression means search for at least one or more consecutive spaces.
Just for learning, remove that plus sign and see what happens,
numberList = round(rand(1,10)*10);
s = ['Record',regexprep(num2str([1,numberList]),' ',',')];
% ^ only 1 space
更多回答(1 个)
Steven Lord
2019-6-18
编辑:Steven Lord
2019-6-18
If you're using a release that supports string convert your numeric vector into a string using string. Next use join to combine the elements of that string array into one string, each separated by a delimeter. Finally concatenate the result to the end of a header string with +. I separated the steps into four lines for clarity, but you could do it in one.
vec = [1 2 8 3 5 2 6 3 7 7 7]
strvec = string(vec)
str = join(strvec, ',')
S = "Record " + str
I chose to separate "Record" and the first element of the the vector with a space; remove the last character of the string in the last line if you don't want that.
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