Why does skeletonization sometimes reduce horizontal rectangles to single pixels?
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Skeletonization (bwskel) of a horizontal rectangle may sometimes result in a single pixel. Can anybody explain why (the logics) and what to do to resolve this issue (illustrated below)?
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Create black binary image and add four white rectangles
bw = false(30,55);
bw(5:9,5:15) = true; % Placed NW
bw(5:9,30:51) = true; % Placed NE
bw(20:25,5:15) = true; % Placed SW
bw(20:25,30:51) = true; % Placed SE
Show image and corresponding skeletonized image
imshow(bw)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/225690/image.png)
imshow(bwskel(bw))
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/225691/image.png)
For two of the rectangles the skeletons reduce to single pixels. Why?
The same thing does not happen for 45 degr. rotated rectangles.
Rotated version of image
bwrot = imrotate(bw,45);
Show rotated images and its skeletonized counterpart
imshow(bwrot)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/225692/image.png)
imshow(bwskel(bwrot))
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/225693/image.png)
For 90 degr. rotated rectangles the same two rectangles reduces to single pixels when skeletonized. However, the pixels are now placed differently.
bwrot = imrotate(bw,90);
Show rotated images and its skeletonized counterpart
imshow(bwrot)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/225694/image.png)
imshow(bwskel(bwrot))
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/225695/image.png)
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采纳的回答
Matt J
2019-6-20
编辑:Matt J
2019-6-20
It is because the lower rectangles have an even number of rows, so their "center line" in continuous space does not coincide with the centers of a line of pixels.
To resolve, make the number of rows odd, e.g.,
bw = false(30,55);
bw(5:9,5:15) = true; % Placed NW
bw(5:9,30:51) = true; % Placed NE
bw(21:25,5:15) = true; % Placed SW
bw(21:25,30:51) = true; % Placed SE
3 个评论
Matt J
2019-6-21
It's a mystery to me. Fortunately, though, if we loop over the odd numbers,
for recth = 1:2:maxrecth
a line skeleton is always observed.
更多回答(1 个)
Catalytic
2019-6-20
Remember what bwskel is doing. It is peeling the outer pixels of the rectangles like an onion over and over again until it reaches a shape that is 1 pixel wide. Because the bottom 2 rectangles have an even number of pixel rows, this process can be repeated until the shape essentially disappears.
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