Converting a cell type data to a 4d format

Question

Saugata Bose 2019-6-25

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https://ww2.mathworks.cn/matlabcentral/answers/468853-converting-a-cell-type-data-to-a-4d-format

编辑： Saugata Bose 2019-6-26

Hi,

I struck into a phase where my data came into one format and I need to reshape it to other format. I have tried reshape and permute, yet, I did not achieve the ultimate result. Would you please help me to get the result. And I would really appreciate if you would please explain your solution.

Input:

A={5 x 1} cell type data where every cell is in this format {300 x 18 single}

Expected Output:

I expect to have an output where each element of A will be formatted as 18 x 300 x 1 x 1 structure.

I have tried to implement the following code to format A but I did not achieve the expected result.

z = cellfun(@(X) permute(X,[3 2 1]),A,'UniformOutput',false);

I am looking for your advice in this regard.

Thanks

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Saugata Bose 2019-6-26

@madhan: Hi. I would expect each cell from A(of size 300 x 18) will turn into a 18 x 300 x 1 x 1, 18 x 300 x 1 x 2, 18 x 300 x 1 x 3, 18 x 300 x 1 x 4 and 18 x 300 x 1 x 5 format. I am not sure though, whether it is possible or not. what you think?

per isakson 2019-6-26

What's the meaning of the colons in A(1,:1,:1,:1) ?

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Answer 1

madhan ravi 2019-6-26

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Try this:

AA=cellfun(@(x) x.',A,'un',0);
Wanted = cat(4,AA{:})

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madhan ravi 2019-6-26

编辑：madhan ravi 2019-6-26

Bose keep the facts straight the latter comment you made seems to contradict the original question before you edited.

:1 is not a valid MATLAB syntax

Saugata Bose 2019-6-26

@Madhan. I absolutely agree. this is my wrong understanding. So to access each of the 4 d element seperately I need to acces by A(:,:,:,1). Thanks for such a solution. I'll edit my post to undo my wrong output expectation.

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Answer 2

KSSV 2019-6-26

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https://ww2.mathworks.cn/matlabcentral/answers/468853-converting-a-cell-type-data-to-a-4d-format#answer_380810

在 MATLAB Online 中打开

% CReate random input for demo 
A = cell(5,1) ; 
for i = 1:5
    A{i} = rand(300,18) ; 
end
B = zeros(18,300,5) ;
for i = 1:5
    B(:,:,i) = A{i}' ;
end