Implementing an equation in Matlab

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Saugata Bose 2019-6-27

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https://ww2.mathworks.cn/matlabcentral/answers/469226-implementing-an-equation-in-matlab

评论： darova 2019-6-28

Hi,

I am trying to implement an equation in a form like, if a*b<1 then, x=-b/N otherwise x=0, where N= size of a. The equation is simple, but the data I recieve for a and b are differnt formet. a is a 4-d numeric array and b is a categorical array. Would you please suggest me how could I implement this equation?

Sample Input

a= val(:,:,1,1)=0.55

val(:,:,2,1)=0.45

val(:,:,1,2)=0.67

val(:,:,2,2)=0.33

I have tried to solve it my way like following:

[m,n,o,p]=size(a,4);
x=zeros(m,n,o,p);
c=double(string(categorical(b)));
for i=1:p
    for j=1:o
        mul=c(i)*a(:,:,j,i);
        if(mul<1)
            x(:,:,j,i)=-c(i)/p;
        else
            x(:,:,j,i)=0;
        end
    end
end

Is it the right way to solve the equation?

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Saugata Bose 2019-6-28

@darova: As the equation is like if the result of a*b is less than 1 then the value of X would be -b/N.

Inb my problem a must be a 4-d numeric array of shape (1 x 1 x i x j), where i is the category, and j is the observation ID and b must be taken as a categorical vector.

a= val(:,:,1,1)=0.67 (it means, the probability of the first observation stays in category 1 is 0.67)

val(:,:,2,1)=0.33( it means, the probability of the first observation stays in category 2 is 0.33)

However, c(1) refers the calue of first category, in my case, it is 0 where as c(2) refers the value of second category which is 1 here.