A problem related to symbolic function.

1 次查看（过去 30 天）
Angus Wong
Angus Wong 2019-7-2
评论： Angus Wong 2019-7-2
I know that if a want to check if a variable is a function handle, then I can use isa(fun,'function_handle').
What should I type in the 2nd input on the isa function to determine if a variable is a symbolic function? I mean I want the output to be 1 if the variable is a symbolic function, and 0 if it isn't. I am expecting something like: isa(fun,'symbolic_function'). (However, it does not work on my computer.)
* fun is the name of the variable to be determined.

请先登录，再回答此问题。

采纳的回答

Alex Mcaulley
Alex Mcaulley 2019-7-2
编辑：Alex Mcaulley 2019-7-2
Try this:
isa(fun,'symfun')

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Symbolic Math Toolbox 的更多信息

标签

产品


版本

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by