Splitting of a column to multiple columns

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Olu B 2019-7-9

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编辑： Stephen23 2019-7-12

Hi,

If I have a 100 x 1 column of numbers between -1 to 100 and i want to eliminate the 0's and negative numbers, then split the column into 10 rows each and call each row a given name so as to plot them against each other.

Could you advise how to do this, thanks

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jahanzaib ahmad 2019-7-9

sir @Stephen Cobeldick whats the easy way to split 100x1 into 10 columns of 10x1

a=n(1:10,:);b=n(11:20,:);c=n(21:30,:);d=n(31:40,:);e=n(41:50,:);f=n(51:60,:);g=n(61:70,:);h=n(71:80,:);i=n(81:90,:);

j=n(91:100,:);

Stephen23 2019-7-10

编辑：Stephen23 2019-7-10

" whats the easy way to split 100x1 into 10 columns of 10x1 "

There is no easy way to do that "automatically". In fact, you should avoid doing that (unless you want to force yourself into writing slow, complex, buggy code which is hard to debug).

The best solutions would be to either reshape the array (e.g. as Renato shows), or split the data into a cell array (e.g. using num2cell or mat2cell).

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回答（1 个）

Renato SL 2019-7-9

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After doing what Stephen Cobeldick suggested in the comments, I believe this would do it.

n2 = reshape(n,[],10);

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Renato SL 2019-7-10

For that, I recommend using reshape function again. I think it would look like this.

Say you have matrix n (1000 by 1) originally, then

n = [1:1000]';
n2 = reshape(n,10,10,10);

so that n would be reshaped into a (10 by 10 by 10) matrix. The first 100 entries then would look like

n2(:,:,1)
ans =
  11    21    31    41    51    61    71    81    91
  12    22    32    42    52    62    72    82    92
  13    23    33    43    53    63    73    83    93
  14    24    34    44    54    64    74    84    94
  15    25    35    45    55    65    75    85    95
  16    26    36    46    56    66    76    86    96
  17    27    37    47    57    67    77    87    97
  18    28    38    48    58    68    78    88    98
  19    29    39    49    59    69    79    89    99
  20    30    40    50    60    70    80    90   100
    

The second 100

n2(:,:,2)
ans =
 111   121   131   141   151   161   171   181   191
 112   122   132   142   152   162   172   182   192
 113   123   133   143   153   163   173   183   193
 114   124   134   144   154   164   174   184   194
 115   125   135   145   155   165   175   185   195
 116   126   136   146   156   166   176   186   196
 117   127   137   147   157   167   177   187   197
 118   128   138   148   158   168   178   188   198
 119   129   139   149   159   169   179   189   199
 120   130   140   150   160   170   180   190   200
   

and so on.

Then to keep each 100 as separate matrices, simply do something like

n100 = n2(:,:,1);
n200 = n2(:,:,2);
%and so on

Olu B 2019-7-11

Thanks for your help. This works

Stephen23 2019-7-12

编辑：Stephen23 2019-7-12

@Olu B: note that splitting up your data makes it harder to work with.

Using indexing is much simpler.

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