For Loop Iteration With Part of Vector

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Kelly McGuire
Kelly McGuire 2019-7-9
评论： Kelly McGuire 2019-7-11
I want to use a row vector to index in a for loop. But, I want to switch to a different function when the index reaches a certain element in the vector. My row vector (t) is 1x1271810. I would like to use my first function in a for loop up to element 945665 in the vector, and then use a different function for the rest of the for loop (or another for loop) from element 945666 to 1271810. Is this possible? Here is how I have my for loop written so far, how would I modify it?:
[a,b] = size(t);
for i = 1:a
for j = 1:b
PredCurrFun(i,j) = p(4).*((1-calcPinf(p,t(i,j),Co(i),Diff)).* ...
exp(-calcLambda(p,t(i,j),Co(i),Diff) .* t(i,j)) + calcPinf(p,t(i,j),Co(i),Diff));
end
end
"second function I would like to use is a 1 - exponential"

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Charles DeLorenzo
Charles DeLorenzo 2019-7-10
编辑：Charles DeLorenzo 2019-7-10
I would suggest using one for loop the length of 't' and a conditional statement to switch between the functions. As an example
for i=1:width(t)
if i<945665
% function 1
else
% function 2
end
end
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Charles DeLorenzo
Charles DeLorenzo 2019-7-11
I'm glad I was able to get you a little further along.
I see why my first answer was confusing, since I did not include both dimensions of the array 't'. You did good by nesting the two for loops on i and j. My answer should have been
[a,b]=size(t)
for i=1:a
for j=1:b
if j<945665
% function 1
else
% function 2
end
end
end
as you already have.
It's hard for me to troubleshoot your code segment above without being able to run it, so I cannot provide a definitive answer on why the second function isn't being used. I would suggest using a conditional breakpoint to stop the if statement when j=945665 to see what's going on. Then, you can manually step the code to see if the second function is being calculated. Conditional breakpoints are under the 'Editor'-->'Breakpoints'-->'Set Breakpoint'. The 'Debug' menu will appear under 'Editor' after the code runs with the breakpoint.
Kelly McGuire
Kelly McGuire 2019-7-11
Great, thanks for the advice! That was very helpful.

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