Error in a for loop

1 次查看（过去 30 天）

Nikolaos Zafirakis 2019-7-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/471667-error-in-a-for-loop

回答： SaiDileep Kola 2019-7-17

I’m trying to run a loop through some measurement but I keep getting this error "Unable to perform assignment because the size of the left side is 3-by-1 and the size of the right side is 2-by-1." Does anyone know a way around this?

o = B(1:50,2);
for ind = 1:length(o)
  a1(:,ind) = diff(o);
  [c1(:,ind),d1(:,ind)] = find(a1(:,ind)>2^15);
  [e1(:,ind),f1(:,ind)] = find(a1(:,ind)<-2^15);
  o(c1(:,ind)+1:e1(:,ind)) = o(c1(:,ind)+1:e1(:,ind))-2^16;                    % Error Happens here
end

4 个评论
显示 2更早的评论隐藏 2更早的评论

dpb 2019-7-14

No idea what you're trying to explain, sorry.

Show us some data that illustrates what you're after with inputs and expected outputs and how you know those are the right answers given the input.

What is the end starting format and then the "the format I need" for the data? Bound to be a more effective way to code this if we just knew what the problem was/is...

Nikolaos Zafirakis 2019-7-14

Original data

The result after 2 iterations of the code i showed you (I want to run what I showed you in a loop).

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

SaiDileep Kola 2019-7-17

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/471667-error-in-a-for-loop#answer_383536

Hi,

I see that you get the error in 3rd line in the for loop not in the of 4rth line as you mentioned, I think your use case can be realized with the following code.

o = B(1:50,2);

for ind = 1:length(o)

a1 = diff(o);

c1 = find(a1>2^15);

e1 = find(a1<-2^15); %Error happens here

o(c1+1:e1) = o(c1+1:e1)-2^16; % Error doesn't occur here

End