How do I increment the value of a variable after each statement by 1?

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BrokenDreams 2019-7-15

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评论： Steven Lord 2019-7-15

I am trying to solve equations using fmincon. I have around 50 non linear constraints.

At the moment i am defining them like

c(1)=..

c(2)=...

.

c(50)=..

how do i make it simpler like c++ where i can do k=0. c(++k)=....

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Answer 1

KALYAN ACHARJYA 2019-7-15

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编辑：KALYAN ACHARJYA 2019-7-15

在 MATLAB Online 中打开

C=zeros(1,50);
for i=1:50
C(i)=....%
end

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Walter Roberson 2019-7-15

Create an array instead of assigning to individual elements.

Steven Lord 2019-7-15

在 MATLAB Online 中打开

If all your constraints are linear combinations of elements in x, consider writing them as a matrix.

constraints = [-1 1 0 0 0 1 zeros(1, 15); ... % -x(1) + x(2) + x(6);
    0 -1 1 zeros(1, 18); ... % -x(2) + x(3)
    zeros(1, 13) -1 1 zeros(1, 6)]; % -x(14) + x(15)
ceq = constraints*x(:);

Alternately instead of using zeros like I did, you could explicitly type out the 0's. This is more verbose (potentially much more verbose) but would make the structure of your constraint matrices explicit and visible. In the example below, each element of the constraints matrix is a single character wide. I could have typed -1 explicitly, but then to get the coefficients to line up I would need to type " 0" and " 1" in later columns.

N = -1; % N = Negative one
P = 1; % P = Positive one
%                                1 1 1 1 1 1 1 1 1 1 2 2
%              1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1
constraints = [N P 0 0 0 P 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
               0 N P 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
               0 0 0 0 0 0 0 0 0 0 0 0 0 N P 0 0 0 0 0 0];
ceq = constraints*x(:);