How do I maximise Volume of a cylinder such that its Surface Area is less than 10 using fmincon by predicting only either radius or height but not both?
1 次查看(过去 30 天)
显示 更早的评论
Volume= pi*r*r*h
Surface Area= 2*pi*r*(h+r);
i am solving a bigger problem. this simple example will help me to solve the bigger problem. The main point is Fmincon should predict only r or h but not both. The other value has to be computed through the constraint equation. Please give me the full code including function call, objective function and constraint function. Thanks
0 个评论
采纳的回答
Torsten
2019-7-16
编辑:Torsten
2019-7-16
Not possible. Since r and h are interdependent, "fmincon" must be able to vary both and thus predict them simultaneously.
Of course, if we assume that maximum volume will result if we use maximum surface area, we have
10 = 2*pi*r^2 + 2*pi*r*h
and we can solve for h:
h = 5/(pi*r) - r
and insert in the volume formula
max: pi*r^2*(5/(pi*r) - r)
But for bigger problems with more constraints, this does not seem the way to go.
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Lighting, Transparency, and Shading 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!