how to stop changing of a variable?

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Enez Furkan Cihan
Enez Furkan Cihan 2019-7-23
编辑： Stephen23 2019-7-24
Function ...
...
if s<200
logic=1;
else
logic=0;
end
end
end
here I'll explain what I tryna make, assume 's' is a variable result of that firstly starting from 0 and having cumulative summation step by step. Till it arrives at 200, logic equals to 1, so far so good, where it arrives at 200, I want the logic be constant 0 always after at 200, the problem is 's' is decreasing after it got hit by 200. So that it starts to be '1' again. That's the thing I don't want it to be. If it happened in a loop, I'd use 'break', but loops is not used.
For any help, I thank you for your time in advance.

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采纳的回答

Stephen23
Stephen23 2019-7-23
编辑：Stephen23 2019-7-24
Use a nested function:
logic = true;
...
function ...
...
logic = logic && s<200;
...
end
...
Or a persistent variable:
https://www.mathworks.com/help/matlab/ref/persistent.html
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Enez Furkan Cihan
Enez Furkan Cihan 2019-7-23
@Stephen Cobeldick , I did solved the problem using persistent. For other people possible may have the same problem I had, I forgot to mention the code is in MATLAB Function in Simulink, and function is called multiple times naturally. Any way, It’s done.
Stephen23
Stephen23 2019-7-24
@Enez Furkan Cihan: I am glad that my suggestion of using peristent helped you. You can help me by voting for my answer or accepting it.

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更多回答（1 个）

Image Analyst
Image Analyst 2019-7-23
Instead of this
if s<200
logic=1;
else
logic=0;
do this
logic = s < 200; % Just one line, not a whole if/else block.
if logic
return; % Exit out of the function entirely so s does not get altered anymore.
end
  1 个评论
Enez Furkan Cihan
Enez Furkan Cihan 2019-7-23
Function is not only set up for this logic part. I can't go out of the function before it completes its sampling time.

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