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How can I add 'ones' until I get a length of 7 digits

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Juan Rosado
Juan Rosado 2012-9-3
I have a vector consisting on < 1 x 3 double > that I would like to add ones until the seventh value is reached.
The variable input is this:
x = [1,2,3];
I want this vector:
x = 1 2 3 1 1 1 1 % length of 7
I can't type the 'ones' directly. I am looking for a code that automatically takes any vector of length less than 7 and add values of 'ones' until the seventh value is reached.
Can you please help?

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回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-9-3
result=ones(1,7);
result(1,1:length(x))=x
Image Analyst
Image Analyst 2012-9-3
编辑：Image Analyst 2012-9-3
If you know for a fact that x is less than 7 long, and you want to stuff the new array back into x, you can do this:
x = [x, ones(1, 7 - length(x))];
The code below is more robust in that it will work for x's both less than 7 long, and longer than 7. If x is longer than 7 this crops the x so that the final array is only 7 long, but you could tack on the whole thing and get the longer array (full and complete x) if you wanted to by just eliminating the else block.
x = [1,2,3];
tempx = x;
lengthOfx = length(tempx)
x = ones(1, 7);
if lengthOfx <=7
x(1:lengthOfx) = tempx
else
x = tempx(1:7)
end
Star Strider
Star Strider 2012-9-3
My variations in terms of anonymous functions:
V7 = @(x) [x (length(x) < 7)*ones(1, 7-length(x))];
Vn = @(x,n) [x (length(x) < n)*ones(1, n-length(x))];

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