From cell array to matrix

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Lev Mihailov
Lev Mihailov 2019-7-25
评论： Andrei Bobrov 2019-7-25
Hello! I have cell arrays, help me deal with the loop.
for i = 1:length(Animal)-1
Y=[X{i}];
end
data looks like this % X{1}=[0] X{2}=[0 1.2 1.4 1.6] X{3}=[0] X{4}=[0 1.3 1.5 1.6]....
My task is to create a 4x800 matrix, where if zero is the column [0 0 0 0], and the values ​​will be in the column

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2019-7-25
Y = cell2mat(cellfun(@(x)[x(:);zeros(4-numel(x),1)],X,'un',0));
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Andrei Bobrov
Andrei Bobrov 2019-7-25
Hi Lev!
Please attach your data X as mat-file.
Andrei Bobrov
Andrei Bobrov 2019-7-25
Variant:
n = cellfun(@(x)numel(x(:)),X);
m = max(n);
k = numel(X);
Y = zeros(m,k);
for ii = 1:k
Y(1:n(ii),ii) = x{ii};
end

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更多回答（1 个）

Felix Albrecht
Felix Albrecht 2019-7-25
Try preallocating with zeros:
Y = zeros(4,800);
% Assuming that length(Animal)-1 = 800
for i = 1:length(Animal)-1
Y(:,i) = X{i};
end
  2 个评论
Lev Mihailov
Lev Mihailov 2019-7-25
编辑：Lev Mihailov 2019-7-25
Y = zeros(4,800);
% Assuming that length(Animal)-1 = 800 length(Animal)=801
for i = 1:length(Animal)-1
Y(:,i) = X{i}; % X{i} 1x800
end
Index exceeds matrix dimensions.
Error in Max_int2407edt (line 9408)
what could be wrong?

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