specific pattern from the file name

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ayman mounir
ayman mounir 2019-7-26
编辑： ayman mounir 2019-7-28
I want to extract the project number from the file name
example the file fame is: 'abcdd-22_Z12'
the project number should be Z12 for sure it is dynamic name could in the next file name Z11 for intance.
which expression I should use

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采纳的回答

per isakson
per isakson 2019-7-26
编辑：per isakson 2019-7-26
These statements
%%
chr = 'abcdd-22_Z12';
cac = regexp( chr, '(?<=_)Z\d{2}', 'match' );
cac{:}
return
ans =
'Z12'
This regex, '(?<=_)Z\d{2}', matches a literal "Z" followed by two digits, which is preceded by underscore.

更多回答（1 个）

Walter Roberson
Walter Roberson 2019-7-26
[~, basename, ext] = fileparts(FileName);
parts = strsplit(basename, '_');
project = parts{end};
In some cases this can be simplified: for example if the directory and extension are already removed from FileName then
project = regexp(FileName, '(?<=_).*', 'match');

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