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How do I compare each value and take the average of same number of every comparison in a vector?

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Masud Rana
Masud Rana 2019-8-6
评论： Adam Danz 2019-8-6
I have a matrix A=[1124x1]. I want to check each element with the next element of the matrix A. If these elements are same then want the average value of them and result will be a matrix [Nx1] where N will be number of different element in the matrix A
for example A=[95; 95; 95; 96;96;96;97;97;97] and result will be [95;96;97].
Thank you
  2 个评论
Adam Danz
Adam Danz 2019-8-6
编辑：Adam Danz 2019-8-6
"...result will be a matrix [Nx1] where N will be number of different element in the matrix A"
unique(A,'stable')
But that is not the average of those groups. Is the unique() function what you were looking for?
If the input/output pattern below if your goal, see the following solution.
A=[95;95;95;96;96;96;97;97;97;95;95;96]; %input
B=[95;96;97;95;96]; %output
idx = [true;diff(A)~=0];
B = A(idx);

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回答（2 个）

the cyclist
the cyclist 2019-8-6
Will identical values every be separated from each other? If not, then it seems like you just need
unique(A)
But this will not give you what you want if
A = [95 95 96 96 97 97 95 95]
Dave
Dave 2019-8-6
In which case if A = [95 95 96 96 97 97 95 95], then you could just sort(A) and then apply unique.

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