Modifying a structure array

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Hi. I am working with a structure array, and I want to modify the structure based on a condition on the field entries.
For example,
Here is the input,
S(1).f1=[1:100] and S(2).f2=[2:101];
S(2).f1=[40:120] and S(2).f2=[60:140]
S(3).f1=...... and S(3).f2=.....
S(4).f1=.... and S(4).f2=.....
.
.
S(i).f1=.... and S(i).f2=....
Can anyone suggest me some smart way to do this.
Conditions on input Output
S(1).f1>=0 and S(1).f1<=50 then ------> S(1).f1=[1:50] and S(1).f2=[2:51]
S(1).f1>50 and S(1).f1<=100 then ------>S(2).f1=[51:100] and S(2).f2=[52:101]
.... so on
Now, the same process for original/input S(2).f1, S(3).f1 .... S(i).f1 to re-form the structure.
After, modification the final step is to delete S(i) if the size of S(i).f1 is < 5.
  3 个评论
SS
SS 2019-8-12
Hi Rik. The order doesn't matter, I just want them them to form a new column. It is from some biological process and I have to break the structure for a span of 50 units of a given field.

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采纳的回答

Bruno Luong
Bruno Luong 2019-8-12
编辑:Bruno Luong 2019-8-12
S=struct;
S(1).f1=5*[2,3,4,5,6,7,8,10,14,16,18,20];
S(1).f2=5*[3,6,9,12,15,18,21,24,27,30,33,36];
S(2).f1=40:120;S(2).f2=60:140;
S(3).f1=20:100;S(3).f2=40:120;
filtfun = @(s) s.f1>=0 & s.f1<=50; % adapt to your need
b = arrayfun(filtfun, S, 'unif', 0);
Sfilter = arrayfun(@(s,b) structfun(@(a) a(b{1}), s, 'unif', 0), S, b); % your reasult
I let you do the deletion step.
  12 个评论
Rik
Rik 2019-8-26
Neither code section produces the error you indicate. You should try to find a data line that causes this error. That is one of the hallmarks of an MWE: the smallest section of data and code that produces the error.
Often when trying to create an MWE you already find the mistake on your own. I have sometimes started writing my own question, when I found the mistake when creating an MWE for my post.
Bruno Luong
Bruno Luong 2019-8-26
编辑:Bruno Luong 2019-8-26
SS: "Hi again. I have tried to use the above code and unfortunately, it gives the follwoing error."
This error is expected to me because you wrote:
"For each S(i), the length of the field arrays is same throughout except 5 fields. The length of these 5 fields is 1 less than the other 25 field arrays. The last element in the these fields can be conisder as zero or empty, it doesn't matter."
Actually it does MATTER, contrary to what you wrote.
And I have warned you long ago.
"I let you deal with the exception of one less element on 5 fields (that's messy condition, and bad data structure design), you better fill them with trailing 0 or NaN, whatever suitable for you, to make all the fields have the same length."

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更多回答(1 个)

Rik
Rik 2019-8-11
编辑:Rik 2019-8-11
Since you don't provide any indication of how you want this to work for struct array input, you'll have to modify this code yourself.
S=struct;
S(1).f1=[2,3,4,5,6,7,8,10,14,16,18,20];
S(1).f2=[3,6,9,12,15,18,21,24,27,30,33,36];
L=S(1).f1<=10;
if sum(L)>=5
S(2).f1=S(1).f1(L);
S(2).f2=S(1).f2(L);
end
S(1).f1(L)=[];S(1).f2(L)=[];
Edit:
%create input struct
S=struct;
S(1).f1=5*[2,3,4,5,6,7,8,10,14,16,18,20];
S(1).f2=5*[3,6,9,12,15,18,21,24,27,30,33,36];
S(2).f1=40:120;S(2).f2=60:140;
S(3).f1=20:100;S(3).f2=40:120;
%create the cell array that will hold the struct elements
c=cell(2,numel(S));
for n=1:numel(S)
c{1,n}=S(n);
L=S(n).f1<=50;
if sum(L)>=5
c{2,n}.f1=S(n).f1(L);
c{2,n}.f2=S(n).f2(L);
end
c{1,n}.f1(L)=[];c{1,n}.f2(L)=[];
end
%reshape back to a struct
S=[c{:}];
  4 个评论
SS
SS 2019-8-12
编辑:SS 2019-8-12
Thank you. What should be the approach if these are not numbered fields and some specific names?
Rik
Rik 2019-8-12
The .() syntax works for char array inputs (and scalar strings).

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