Expected one output from a curly brace or dot indexing expression, but there were 2 results.
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Hi.I working with a code to manipulate some data and here are the lines which gives error
S12(m).x2(n)=S2(tn4).x(ts4) % line 104
S12(m).dx2(n)=S2(tn4).dx(ts4) % line 105
S12(m).z(n)=S2(tn4).y(ts4) % line 106
The error is,
Expected one output from a curly brace or dot indexing expression, but there were 2 results.
Error in data_man (line 104) S12(m).x2(n)=S2(tn4).x(ts4)
How can I fix this error?
3 个评论
采纳的回答
Bruno Luong
2019-8-13
编辑:Bruno Luong
2019-8-13
In general you are not allow to assign multi-level structures with non-scalar indexing in one shot, you need to do in 2 steps.
% S12(m).x2(n)=S2(tn4).x(ts4)
x2 = {S12(m).x2};
x = {S2(tn4).x};
for k=1:length(x2)
x2{k}(n) = x{k}(ts4);
end
[S12(m).x2] = deal(x2{:});
3 个评论
Chuck Olosky
2020-8-2
This approach worked for:
names = {'a' 'b' 'c'};
dStruct = repmat(struct('name',''),size(names));
[dStruct.name] = deal(names{:});
Also works without "deal":
[dStruct.name] = names{:};
In other threads, there are discussions regarding "deal" being unnecessary in later releases.
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