How Read text file as array form , Please

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Furat Alobaidy
Furat Alobaidy 2019-8-21
评论： Furat Alobaidy 2019-8-21
Hi ,
i have text file (data) , i need store each word or number as array (x,y):as in attach file
for example:
line 1: 413733000: system.cpu15.icache: ReadReq [10574:10577] IF hit state: 5 (S) valid: 1 writable: 0 readable: 1 dirty: 0 tag: 8
line2: 413733000: system.cpu00.icache: ReadReq [6e4ef8:6e4efb] IF hit state: 5 (S) valid: 1 writable: 0 readable: 1 dirty: 0 tag: 372
store in array as :
c(1,1)=413733000 c(1,2)= system c(1,3)=cpu15 c(1,3)= icache ...etc. to the line 1
c(2,1) =413733000 c(2,1)=system c(2,2)=cpu00 c(2,3)=ichahe ..etc.. to the line 2
i appricate for any help
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Rik
Rik 2019-8-21
You misunderstood: I meant what code did you already try.
Also, it might be a better idea to parse each line, instead of chopping it up into smaller pieces. And you probably want a struct array.
Furat Alobaidy
Furat Alobaidy 2019-8-21
filename = 'C:\xxx\sample2.txt';
fileID = fopen(filename);
%c = textscan(fileID,'%s %s %s %s %s %s %s %s %s %s %s %s %s %s %s %s %s %s %s[^\n]' );
fclose(fileID);
but its gave me just one vector c(1) {19) for all lines !
i need matrix : rows = lines (1..2)
colums = (1..19)
"Also, it might be a better idea to parse each line, instead of chopping it up into smaller pieces. And you probably want a struct array."
can provide me more hints please

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回答（1 个）

Rik
Rik 2019-8-21
The code below should get you most of the way there. The idea is to parse each element and then remove it from the variable, so every part is independent and can in principle be replaced by some parsing function you would write. This code does rely on you having read the file to a cell array, but that shouldn't really be a problem. You can even use my readfile FEX function if you're in a hurry.
c={'413733000: system.cpu15.icache: ReadReq [10574:10577] IF hit state: 5 (S) valid: 1 writable: 0 readable: 1 dirty: 0 tag: 8',...
'413733000: system.cpu00.icache: ReadReq [6e4ef8:6e4efb] IF hit state: 5 (S) valid: 1 writable: 0 readable: 1 dirty: 0 tag: 372'};
out=struct;
for n=1:numel(c)
str=c{n};
idx=strfind(str,':');
ID=str(1:(idx(1)-1));
str(1:(idx(1)+1))='';%chop off ID
idx=strfind(str,':');
CPU=str(1:(idx(1)-1));
str(1:(idx(1)+1))='';%chop off CPU
idx1=strfind(str,'[');idx1=idx1(1)+1;
idx2=strfind(str,']');idx2(idx2<idx1)=[];idx2=idx2(1)-1;
MemoryAddress=str(idx1:idx2);
str(1:(idx2+2))='';%chop off MemoryAddress
%etc
%store to output struct
out(n).ID=ID;
out(n).CPU=CPU;
out(n).MemoryAddress=MemoryAddress;
%etc
end
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Rik
Rik 2019-8-21
Have you read the documentation for fopen? It generates a handle to a file, it isn't the file contents. If you have an error or unexpected output when using a function, read the documentation first.
Either use fgetl (and replace the for-loop by a while loop, don't forget setting n to 0 and incrementing it inside the loop) or use my readfile function. Note that it is often much faster to load the entire file that to read line by line.

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