Downsampling an image

13 次查看（过去 30 天）
Venkat R
Venkat R 2011-4-5
Hi everybody,
I want to downsample a 49x49 image into 7x7 image using gaussian filter of 31x31. The alternate approach I tried (but not getting the accurate result) is as follows.
Any help is very much appreciated.
with regards, Venkat
clear all,clc
I = imresize(imread('pout.tif'),[49 49]); % I used matlab image as example of 49x49 image instead of my experiment image
hgausspymd = video.Pyramid;
hgausspymd.PyramidLevel = 3;
I_down = mat2gray(double(step(hgausspymd, I)));
imshow(I_down)
  2 个评论
David Young
David Young 2011-4-5
Why 31x31 for the filter? This is an enormous filter to apply to a 49x49 image, and will give rise to serious problems at the image boundaries, since it will only be wholly inside the image when centred on pixels in the middle 19x19 square.
Image Analyst
Image Analyst 2011-9-17
Exactly what does "accurate" mean to you? As David says the final output image will be nearly all edge effects since very little will fit the 31x31 filter. There are a variety of ways to take edge effects into account. Which way do you prefer? Which way are you using when you define accuracy?

请先登录，再进行评论。

请先登录，再回答此问题。

回答（2 个）

Oliver
Oliver 2011-9-17
a(1:2:end,1:2:end)
  1 个评论
Walter Roberson
Walter Roberson 2011-9-17
That would downsample to 25 x 25 rather than 7 x 7, and would not use a gaussian filter as asked by the original poster.

请先登录，再进行评论。

Venkat R
Venkat R 2011-9-18
Dear friends, thanks for your comments.
I am using the following code.
"accurate" means, should be able to summarize the information content in 49x49 images. Not just the peak/central regions etc
h = fspecial('gaussian',[31 31],3.5);
idown= imfilter(bw4,h,'symmetric');
bw4 is a 17x17 matrix. If I take first 7 alternative values in it, it is serving me the purpose
with regards, Venkat

类别

在 Help Center 和 File Exchange 中查找有关 Image Category Classification 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by