A BAD way to code:
B=min(A):1/9:max(A); % linear 10 pieces
A better way to code, for the same target result:
B=linspace(min(A),max(A),10); % linear 10 pieces
Learn to use the tools in MATLAB properly, here, linspace is a terribly valuable tool.
Why is linspace better? Because if you explicitly want 10 values that are linear over that interval, linspace gives you them, and does so accurately. You only need to indicate the NUMBER of elements, thus an integer value.
What happens when you use colon, and you specify the increment? Here, you need to be careful, to compute the correct spacing yourself.
A=[0.1, 0.21, 0.346, 0.59, 0.744, 1]
A =
0.1 0.21 0.346 0.59 0.744 1
B=min(A):1/9:max(A)
B =
0.1 0.21111 0.32222 0.43333 0.54444 0.65556 0.76667 0.87778 0.98889
length(B)
ans =
9
B(end)
ans =
0.988888888888889
B=linspace(min(A),max(A),10)
B =
0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1
length(B)
ans =
10
Do you see what happened? The increment that you used was not in fact correct. The last element of B when you created it using colon was
B=min(A):1/9:max(A);
B(end)
ans =
0.988888888888889
It was not 1, because 1/9 is not the correct increment to achieve that result. You made an error of thought, using the wrong increment.
Again, learn to use linspace, because that makes your code better. It prevents you from making simple mistakes.
