How to graph a patch that follows a line?

3 次查看（过去 30 天）
Philippe Corner
Philippe Corner 2019-9-4
评论： Philippe Corner 2019-9-5
I'm trying to export my figure without background using the attached code. As you may see, I'm using a patch function to cover a very small area, I want to use a smaller patch that follows the red line (see line 91). Any ideas about how to do it?
Slide1.jpeg
The idea is tha my patch does follow only YL = ylim, but it follows the same tendency of red line line, and with a small thikness, maybe 1 unit or something like that.
clear;clc
A=[ -12.236 1417.575 3.629 0.2756 6.495
-4.239 1416.849 1.700 0.5884 10.726
3.764 1415.702 8.779 0.1139 18.386
11.765 1414.657 19.057 0.0525 0.357
19.767 1413.565 23.490 0.0426 1.128
27.773 1412.141 6.767 0.1478 2.323
35.778 1410.820 6.459 0.1548 0.816
51.771 1409.493 13.318 0.0751 0.005
67.743 1409.605 2.851 0.3507 19.542
75.736 1409.051 4.407 0.2269 0.005
83.685 1409.926 3.746 0.2670 6.940
91.646 1410.386 6.075 0.1646 21.096
99.640 1409.575 8.106 0.1234 5.910
107.620 1409.047 7.330 0.1364 12.873
123.623 1407.111 19.248 0.0520 4.626
131.608 1406.459 19.462 0.0514 4.579
155.748 1398.703 10.460 0.0956 4.238
163.770 1396.466 10.020 0.0998 1.405
171.768 1395.721 9.112 0.1097 0.925
179.769 1394.702 10.088 0.0991 0.347
187.762 1394.345 38.594 0.0259 1.539
195.760 1393.510 33.104 0.0302 2.456
203.770 1391.803 22.253 0.0449 4.501
211.773 1390.669 18.235 0.0548 4.996
-4.714 1412.787 11.198 0.0893 11.495
3.294 1411.678 35.189 0.0284 19.953
11.297 1410.652 1.944 0.5143 9.786
19.302 1409.587 22.708 0.0440 2.563
35.329 1406.982 2.800 0.3571 51.108
43.336 1405.852 8.600 0.1163 1.075
51.311 1405.562 24.378 0.0410 3.769
59.264 1405.778 3.745 0.2670 0.405
67.242 1405.315 27.800 0.0360 23.019
75.225 1404.677 32.562 0.0307 0.161
91.021 1405.037 2.033 0.4919 33.104
106.966 1403.454 0.401 2.49 13.230
114.978 1402.459 0.414 2.42 13.897
130.941 1400.754 0.532 1.88 6.411
138.998 1399.510 3.936 0.2540 2.818
147.118 1397.609 6.552 0.1526 1.683
155.255 1394.488 43.711 0.0229 4.206
163.310 1392.528 36.826 0.0272 1.930
171.305 1391.754 25.253 0.0396 1.071
179.307 1390.750 9.461 0.1057 0.656
187.288 1390.294 7.927 0.1261 1.636
195.285 1389.441 26.961 0.0371 2.424
203.310 1387.864 27.695 0.0361 4.414
211.316 1386.764 15.058 0.0664 5.489];
X = A(:,1);
Y = A(:,2);
Z = A(:,3);
[xq,yq]=meshgrid(linspace(min(X),max(X),100),linspace(min(Y),max(Y),100));
zq=griddata(X,Y,Z,xq(:),yq(:),'cubic'); %cubic for smoother results
figure()
[c,h]=contourf(xq,yq,reshape(zq,100,100));
colormap(jet(5))
axis equal
hold on
cota=[ -12.236 1417.575 3.629 0.2756 6.495
-4.239 1416.849 1.700 0.5884 10.726
3.764 1415.702 8.779 0.1139 18.386
11.765 1414.657 19.057 0.0525 0.357
19.767 1413.565 23.490 0.0426 1.128
27.773 1412.141 6.767 0.1478 2.323
35.778 1410.820 6.459 0.1548 0.816
51.771 1409.493 13.318 0.0751 0.005
67.743 1409.605 2.851 0.3507 19.542
75.736 1409.051 4.407 0.2269 0.005
83.685 1409.926 3.746 0.2670 6.940
91.646 1410.386 6.075 0.1646 21.096
99.640 1409.575 8.106 0.1234 5.910
107.620 1409.047 7.330 0.1364 12.873
123.623 1407.111 19.248 0.0520 4.626
131.608 1406.459 19.462 0.0514 4.579
155.748 1398.703 10.460 0.0956 4.238
163.770 1396.466 10.020 0.0998 1.405
171.768 1395.721 9.112 0.1097 0.925
179.769 1394.702 10.088 0.0991 0.347
187.762 1394.345 38.594 0.0259 1.539
195.760 1393.510 33.104 0.0302 2.456
203.770 1391.803 22.253 0.0449 4.501
211.773 1390.669 18.235 0.0548 4.996];
plot(cota(:,1),cota(:,2),'r', 'linewidth',2)
YL = ylim;
XL = xlim;
patch([XL, fliplr(cota(:,1)')], [[1 1]*YL(2), fliplr(cota(:,2)')], 'w')
set(gca,'YTick',[])
set(gca,'XTick',[])
set(gca,'XColor', 'none','YColor','none')
set(gca,'color','none')
  4 个评论
显示 2更早的评论
Philippe Corner
Philippe Corner 2019-9-4
编辑：Philippe Corner 2019-9-4
I want to cover the contour plot that appears above the red line, I already did that, as I showed you on the second figure, but what I want is that may patch does not go on that way, I want my patch to be following the upper border you drew in red, but with a small thickness. Please feel trae to ask again if I’m not being clear.. Cheers

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

darova
darova 2019-9-4
I found boundary points and moved them down a bit
zq(isnan(zq)) = 1000; % replace NaN with big number
ix = find(diff(zq(:)) > 500); % find border indexes
plot(xq(ix),yq(ix)-0.5,'*-r')
Here is what i get
img1.png
  3 个评论
显示 1更早的评论
darova
darova 2019-9-4
Just concantenate data:
xc = [cota(:,1); flipud(xq(ix))];
yc = [cota(:,2); flipud(yq(ix))];
patch(xc,yc,'w')
Or you can just replace data with NaN in between those lines:
xc = [cota(:,1); flipud(xq(ix))];% just concantenate data
yc = [cota(:,2); flipud(yq(ix))];
in = inpolygon(xq(:),yq(:),xc,yc);
zq(in) = nan;
[c,h] = contourf(xq,yq,zq);
Philippe Corner
Philippe Corner 2019-9-5
That's very nice, thanks a lot for the help!

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Lighting, Transparency, and Shading 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by