ignore or delete number or row has been multiply defined?

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hell everyone!
I have an example:
if i have an array like this: [1 2 3 4 5 6 7 8 9 10 ...
1 2 11 12 13 14 ]
you can see that number: 1 and 2 is multiply defined: is twice.
How can i delete row has been multiply defined: like you just 1 time defined the number if 2 time defined that number then delete that number or entire rows of that number from matrix?
Results is: [1 2 3 4 5 6 7 8 9 10 11 12 13 14];
Tks.
LXT

采纳的回答

Akira Agata
Akira Agata 2019-10-4
Simple solution will be:
result = unique(yourArray);
If you want to keep element's order, please try the following:
[~, ia] = unique(yourArray);
result = yourArray(sort(ia));

更多回答(1 个)

David Hill
David Hill 2019-10-4

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