find values from a matrix according to a criterion

1 次查看（过去 30 天）
Richard
Richard 2012-9-17
I have a time series of measurements as follows:
time = [733774,733774,733775,733775,733775,733776,733776];
data = [1,1.3,1,2.5,2.5,1,1.2];
Final = [time',data'];
I want to create a new variable that only contains the values that contain more than two measurements for individual days. So, from the example above, the result should be:
newData = [[733775;733775;733775],[1;2.5;2.5]];

请先登录，再回答此问题。

采纳的回答

José-Luis
José-Luis 2012-9-17
time = [733774,733774,733775,733775,733775,733776,733776];
data = [1,1.3,1,2.5,2.5,1,1.2];
unik_time = unique(time);
rep_time = arrayfun(@(x) (sum(ismember(time,x)) > 2),unik_time);
idx = ismember(time,unik_time(rep_time));
your_time = time(idx);
your_vals = data(idx);

更多回答（1 个）

Thomas
Thomas 2012-9-17
Something like this
time = [733774,733774,733775,733775,733775,733776,733776];
data = [1,1.3,1,2.5,2.5,1,1.2];
Final = [time',data'];
unique_days=unique(time);
for ii=1:length(unique_days)
count(ii)=sum(unique_days(ii)==time);
end
idx=find(count>2);
% If there is more than 1 day with 3 or more readings
for jj=1:length(idx)
idx_time(jj,:)=find(time==unique_days(idx(jj)));
newTime=time(idx_time(jj,:))
newData=data(idx_time(jj,:))
end

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by