There is not just one solution, there is a family of solutions that depends upon the uncertainty in the floating point number 1.87 . In science, 1.87 represents the set of numbers that round to 1.87, so [1.87-0.005, 1.87+0.005) semi-open interval
syms h c delta
assume(-0.005 <= delta & delta < 0.005);
eqn1 = h/c == 1.87 + delta;
x = 110;
eqn2 = x == h+c;
sol = solve([eqn1, eqn2], [h, c]);
subplot(1,2,1);
fplot(sol.h, [-0.005, 0.005]);
xlabel('uncertainty in 1.87')
ylabel('h');
subplot(1,2,2);
fplot(sol.c, [-0.005, 0.005]);
xlabel('uncertainty in 1.87')
ylabel('c')
