nlparci for log-transformed data

2 次查看(过去 30 天)
Minu Pilvankar
Minu Pilvankar 2019-10-8
Hello,
I am using lsqcurvefit for data fitting of a dataset. I am log-transforming the data to estimate the parameters and am getting a good estimate of the values. But when I use "nlparci" to find the confidence intervals for these parameters, they are really large. "nlparci" gave reasonable confidence intervals when I did not log-transform the data. But I want to use log-transform to later implement log-additive error model. Is there other way to get the confidence interval?
This is what I am doing now:
[PK_params1,resnorm,residual,exitflag,output,lambda,J] = lsqcurvefit(@(PK_params1,xdata)LSQ_MulticompODE_Amount(PK_params1,R,xdatan),PK_paramsguess,xdatan,ydatan,lb,ub,options);
ci = nlparci(PK_params1,residual,'jacobian',J)
percent_error_estimate = ((PK_params1' - ci(:,1))./PK_params1').*100

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Least Squares 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by