Count how many element are inside each cell af a cell array on the basis of an array
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Hi given a cell array
V={{[1,1,1,1;25,45,70,90],[2,2,2,2;78,112,146,180],[3,3,3,3;93,127,161,195],[4,4;70,100],[6;85],[9,9;85,110]},{[],[2,2,2,2;73,107,141,175],[3,3,3,3;83,117,151,185],[4,4,4,4;65,85,105,125],[6;85],[9,9,9;80,105,130]}};
and an array
SP= [1 2 3 4 6 9]
I want to create a matrix M that has as many rows as the cell in V (in this case 2)
CONSIDERING THE FIRST CELL:
Inside the row of M how want to count how many elements are present in each cell of the same type, and that cannot exceed a value of 80 (<80) referring to the second raw of each cell.
considering element 1 in V{1,1} that occupies V{1,1}{1,1}
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/242833/image.png)
In this case the number of 1 that do not exceed 80 is 3.
take the element 2
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/242834/image.png)
is just 1.
Doing the same for all the elements and cells i ontain M:
M= [3 1 0 1 0 0; 0 1 0 1 0 1]
May someone help me with the code?
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