Writting a loop for calculating difference from previous result of first calculation
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I have 4 variables.
Initial_value = 50;
minimum_Value = 25;
difference_value = 5;
remaining_value = (Result)
I am trying to write a peice of code which can do following operation automatically:
step 1: Initial_value - difference_value = remaining_value
step 2: remaining_value - difference_value = new_remaining_value
step 3: new_remaining_value - difference_value = new_remaining_value_2
.
.
.
.
last step: loop stops when remaining value is equal to or less than minimum_value
To simplify I setup this example:
step 1: 50 - 5 = 45
step 2: 45 - 5 = 40
step 3: 40 - 5 = 35
step 4: 35 - 5 = 30
step 5: 30 - 5 = 25
End of loop as it reached to 25 (minimum value)
I tried writing this but it only calculates till 1 step.
for i = 100
if remaning_value(i) > minimum_value
a(i) = initial_value(i) - difference_value;
initial_value(i) = remaining_value(i);
end
end
Kindly suggest how shall i acheive this goal.
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采纳的回答
Stephen23
2019-10-25
Initial_value = 50;
minimum_value = 25;
difference_value = 5;
remaining_value = Initial_value;
while remaining_value(end)>minimum_value
remaining_value(end+1) = remaining_value(end)-difference_value;
end
Giving:
remaining_value =
50 45 40 35 30 25
3 个评论
Stephen23
2019-10-26
编辑:Stephen23
2019-10-26
"It should stop at 12.58 but it did not."
Think about how while loops actually work: they continue as long as a condition is true and by the time that condition is false, the cause of it being false (e.g. some value being greater than 12.02) has already been calculated and added to your data.
One simple solution is to remove the last element:
while remaining_value(end) >= minimum_value % note: >=
remaining_value(end+1) = remaining_value(end)-difference_value;
end
remaining_value(end+1) = []; % remove last element
See also:
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