Select values from 20 x 15 matrix based on a row vector 1 x 15

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I'm trying to extract values from matrix A (20 x 15) which are less than values in matrix B (1 x 15). Matrix B has 15 columns with threshold values determined from newspaper analysis. How to extract values from each column of matrix A which are less than values from corresponding columns from matrix B?
I have tried C = A < B; but I'm not able to fix matrix dimension error.
  1 个评论
Steven Lord
Steven Lord 2019-11-7
Which release of MATLAB are you using? It may be relevant particularly if you're using a release prior to release R2016b, when we introduced implicit expansion.

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采纳的回答

JESUS DAVID ARIZA ROYETH
solution:
A(A>=B)=nan;
disp(A)
c=num2cell(A,1);
for k=1:size(c,2)
c{k}(isnan(c{k}))=[];
disp(['Column ' num2str(k)])
disp(c{k})
end
  2 个评论
Parthu P
Parthu P 2019-11-7
Thanks for reply.
Actually I have tried the simillar loop before but I'm not able to fix dimension error related to B.
For example, in "C = A < B"
If I make "C = A < B (:,1)" or "C = A < B (:,15)". It read B value in either 1st or 15th column and apply it to all the columns. How do i put right dimensions for "B (. . . . . )", so that it reads correct B value for corresponding individual columns of matrix A?
JESUS DAVID ARIZA ROYETH
This works well for the dimensions you indicated, could you save your workspace and attach it? look at an example:
A=rand(20,15);
B=rand(1,15);
A(A>B)=nan;
disp(A)
c=num2cell(A,1);
for k=1:size(c,2)
c{k}(isnan(c{k}))=[];
disp(['Column ' num2str(k)])
disp(c{k})
end

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更多回答(1 个)

kondepati sudhir kumar
if use the C = A <B; you wil get the logic matrix. If you have dimensional error then it is better give the c = zeros (size (a));
i hope it works.

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