How do I locate all integer values within a matrix (of string and integer values in the same cell), then replace all those integer values with a 1 or 0 thus forming a new matrix with the replaced integers?

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Michael Tross 2019-11-14

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关闭： MATLAB Answer Bot 2021-8-20

"( x(2) | x(1) )"

"x(3)"

"( x(4) | x(6) | x(5) )"

"( x(7) | x(8) )"

""

"x(9)"

"( x(10) & x(11) & x(12) )"

"x(13)"

"( x(15) | x(14) | x(1) )"

The text above are in a column vector, but I need to replace the integers with a zero or one. Eg. All integer values not equal to two should be zeros (x(0)), whereas those equal to two should be '1' (x(1)

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Daniel M 2019-11-14

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I know there's a way to do this in one line, but I'm not great with regular expressions. Here's what I came up with, perhaps you can make it more elegant.

s = ["( x(2) | x(1) )", "x(3)", "( x(4) | x(6) | x(5) )", "( x(7) | x(8) )", "( x(7) | x(8) )", "", "x(9)", "( x(10) & x(11) & x(12) )", "x(13)", "( x(15) | x(14) | x(1) )"];
r = regexprep(s,'\(2\)','(NaN)');
r = regexprep(r,'\(\d*\)','(0)');
r = regexprep(r,'NaN','1');

Michael Tross 2019-11-14

编辑：Michael Tross 2019-11-14

Thank you Daniel! That did the trick!

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Answer 1

Stephen23 2019-11-14

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编辑：Stephen23 2019-11-14

在 MATLAB Online 中打开

Method one: multiple regular expressions in one regexprep call:

>> c = {'( x(2) | x(1) )', 'x(3)', '( x(4) | x(6) | x(5) )', '( x(7) | x(8) )', '( x(7) | x(8) )', '', 'x(9)', '( x(10) & x(11) & x(12) )', 'x(13)', '( x(15) | x(14) | x(1) )'};
>> d = regexprep(c,{'\(2\)','\d+','%%%'},{'(%%%)','0','1'});
>> d{:}
ans =
( x(1) | x(0) )
ans =
x(0)
ans =
( x(0) | x(0) | x(0) )
ans =
( x(0) | x(0) )
ans =
( x(0) | x(0) )
ans =
     ''
ans =
x(0)
ans =
( x(0) & x(0) & x(0) )
ans =
x(0)
ans =
( x(0) | x(0) | x(0) )

Method two: dynamic replacement expression:

>> fun = @(x)num2str(isequal(str2double(x),2));
>> d = regexprep(c,'\d+','${fun($&)}');
>> d{:}
ans =
( x(1) | x(0) )
ans =
x(0)
ans =
( x(0) | x(0) | x(0) )
ans =
( x(0) | x(0) )
ans =
( x(0) | x(0) )
ans =
     ''
ans =
x(0)
ans =
( x(0) & x(0) & x(0) )
ans =
x(0)
ans =
( x(0) | x(0) | x(0) )

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Daniel M 2019-11-14

Ok that is cool. I haven't seen an anonymous function used with regular expressions before. I will definitely be able to make use of this concept.

How do I locate all integer values within a matrix (of string and integer values in the same cell), then replace all those integer values with a 1 or 0 thus forming a new matrix with the replaced integers?

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How do I locate all integer values within a matrix (of string and integer values in the same cell), then replace all those integer values with a 1 or 0 thus forming a new matrix with the replaced integers?

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