IF statement and time display

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Hamza
Hamza 2012-9-26
Dear All
I have a string which displays time and date taken from a txt file using:
str= datestr(datenum([yy mm dd HH MM SS]),0);
output yy =
96
96
96
97
98
99
00
01
I want it to be displayed as 1996 if it is before 2000 and 2000,2001,2002,..so on if after 2000.
Also the 'mm' format being displayed is like Jan,feb,.. can it be displayed as 01,02,03,..12? I couldn't find the proper formatting for it.
Current output example: str = 20-Dec-0003 22:47:39
Thanks

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Andrei Bobrov
Andrei Bobrov 2012-9-26
编辑：Andrei Bobrov 2012-9-26
x= {'96318.74847837'
'96319.62211352'
'96319.62351606'
'96319.62356237'
'96320.05952563'
'96320.49676119'} % initial array
a = str2double(x);
y = fix(a/1000);
ymdhms = datevec(datenum(y,0,a - y*1000)); % corrected
[yearnow,~] = datevec(now);
ymdhms(:,1) = (ymdhms(:,1) <= rem(yearnow,2000))*100 + 1900 + ymdhms(:,1);
out = datestr(ymdhms,'yyyy-mm-dd HH:MM:SS');
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Andrei Bobrov
Andrei Bobrov 2012-9-26
Hi Hamza! Excuse me, I use year as function from the Financial Toolbox. Corrected.
Hamza
Hamza 2012-9-27
编辑：Hamza 2012-9-27
Hey Andrei
It works great now...Thanks a lot!!
I have one last step to cover..can you help?
I will post another question for that.

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