Problem using interp1 with a sharp change in the data

6 次查看（过去 30 天）

Jaime De La Mota Sanchis 2019-11-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/491727-problem-using-interp1-with-a-sharp-change-in-the-data

评论： Jaime De La Mota Sanchis 2019-11-18

interpolation issue.jpg

Hello everyone.

I have a vector of data and I want to interpolate it using interp1. The problem is that there is a sharp increase in the values of the vector and the resulting graph does not reproduce the data propperly.

Is there a way to make the interpolated data reproduce the sharp jump propperly?

I will attach a figure where my issue is displayed.

Any answer is appreciated.

Thank you very much.

Jaime.

5 个评论
显示 3更早的评论隐藏 3更早的评论

Mil Shastri 2019-11-18

Thanks for clarification. What will also help is a clear description of what you want the output to look like.

Jaime De La Mota Sanchis 2019-11-18

在 MATLAB Online 中打开

The code I use is simply

Tinterp=interp1(time,T,t,'spline');

being T a vector which values can be seen in the attached T.txt; the same thing happens with time.

What I do next is plot together T-time and Tinterp and t as

figure
plot(t, Tinterp)
hold on
plot(time, T)
legend('interpolated','original')
title('T Spline')

I hope this clarifies what I am attempting to do.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Steven Lord 2019-11-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/491727-problem-using-interp1-with-a-sharp-change-in-the-data#answer_402068

Try using ischange to detect these sharp changes in your data and interpolating using only data in the same "piece" of your curve (where pieces are delimited by the ends of your data sets and the change points) as the points for which you want the interpolated value.