splitvars for input arguments of type 'cell'

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Deepa Maheshvare
Deepa Maheshvare 2019-11-24
评论： Deepa Maheshvare 2019-11-24
The following contents are stored in a table, in variable 'tbl',
Multico value
______________
{'1'} {'2'} 1
{'2'} {'3'} 2
{'3'} {'4'} 1
{'4'} {'5'} 2
I am trying to split the contents in `Multico`
multico = splitvars(cell2mat(tbl.Multico));
The following error is obtained. Any suggestions on how to split the contents?
Undefined function 'splitvars' for input arguments of type 'cell'.
Expected result:
Multico_1 Multico_2 value
1 2 1
2 3 2
3 4 1
4 5 2
  2 个评论
Walter Roberson
Walter Roberson 2019-11-24
cell2mat() of that variable would give a 4 x 2 char array. splitvars() has to be run on a table and a variable name, not on a char array.
It is not obvious what you would want the result to be.
Deepa Maheshvare
Deepa Maheshvare 2019-11-24
编辑：Deepa Maheshvare 2019-11-24
Many thanks for the reponse. Please have a look at the update made in the original post. Sorry if I wasn't clear. The contents are stored in a table. It is actually the output of the edge
properties of a graph (tbl = Graph.Edges).

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采纳的回答

Guillaume
Guillaume 2019-11-24
As per my comment to your other question, it looks like Multico should be a matrix not a cell array.
Regardless of its type, what you want is simply:
newtable = splitvars(yourtable, 'Multico')
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显示 1更早的评论
Guillaume
Guillaume 2019-11-24
Hum, splitvars works fine regardless of whether Multico is a cell array or a matrix:
>> t = table({'1', '2'; '2', '3'; '3', '4'; '4', '5'}, [1; 2; 1; 2], 'VariableNames', {'Multico', 'value'})
t =
4×2 table
Multico value
______________ _____
{'1'} {'2'} 1
{'2'} {'3'} 2
{'3'} {'4'} 1
{'4'} {'5'} 2
>> splitvars(t, 'Multico')
ans =
4×3 table
Multico_1 Multico_2 value
_________ _________ _____
{'1'} {'2'} 1
{'2'} {'3'} 2
{'3'} {'4'} 1
{'4'} {'5'} 2
>>
Deepa Maheshvare
Deepa Maheshvare 2019-11-24
Sorry, my mistake. I had tried splitvars(tbl.Multicol).

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