Replace initial values of an matrix.

1 次查看（过去 30 天）
Ricardo Gutierrez
Ricardo Gutierrez 2019-11-26
评论： Ricardo Gutierrez 2019-11-27
Hi. Good day.
Waiting for your valuable help.
I have a matrix A (4 X 4) with these initial values
A = [0.3511 1.2091 1.8834 1.5089
     0.5290 1.1016 1.7171 1.2664
     0.9242 1.5412 1.8093 1.0313
     0.5027 1.4695 2.2388 1.1906];
Matrix A is subjected to several mathematical steps and as a result a matrix B is obtained (3 X 4)
B = [0.3512 1.2999 1.8885 1.5588
     0.5299 1.1999 1.9192 1.2787
     0.9292 1.5888 1.8993 1.2589];
It is observed that matrix B is missing a line to be the same size as matrix A
How do I replace the values of matrix B in matrix A by repeating the last line of matrix B?
The new matrix A would look like this
B = [0.3512 1.2999 1.8885 1.5588
     0.5299 1.1999 1.9192 1.2787
     0.9292 1.5888 1.8993 1.2589
     0.9292 1.5888 1.8993 1.2589];

请先登录，再回答此问题。

采纳的回答

JESUS DAVID ARIZA ROYETH
编辑：JESUS DAVID ARIZA ROYETH 2019-11-26
solution in general:
B=B(horzcat(1:size(B,1),repmat(size(B,1),1,size(A,1)-size(B,1))),:)
particular:
B=B([1:3 3],:)

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Multidimensional Arrays 的更多信息

标签

产品


版本

R2014a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by