Delete end points from columns in a structure array

7 次查看(过去 30 天)
Hello.
I have a structure array S (1 x 50000) with 10 fields. The elements in the fields are column matrices (1 X M) with their size consistent for given S(i).
I want to delete tails in all the 10 fields (2 data points on each side - at the beginning and the end of the vector) which, should result in the array size of (1 X M-4).
For example, the input is something like this
S(1).f1=[1,2,3,4,5,6,7,8,9,10];
S(1).f2=[2,4,6,8,10,12,14,16,18,20];
S(2).f1=[10,20,30,40,50,60,70];
S(2).f2=[150,200,250,300,350,400,450];
I want the output to be,
S(1).f1=[3,4,5,6,7,8];
S(1).f2=[6,8,10,12,14,16];
S(2).f1=[30,40,50];
S(2).f2=[250,300,350];

采纳的回答

Andrei Bobrov
Andrei Bobrov 2019-11-27
S = cell2struct(cellfun(@(x)x(3:end-2),struct2cell(S),'un',0),fieldnames(S));
  3 个评论

请先登录,再进行评论。

更多回答(1 个)

Luna
Luna 2019-11-27
编辑:Luna 2019-11-27
I did something like this:
newS2 = arrayfun(@(y) structfun(@(x) x(3:end-2),y,'uni',false),S)
Or:
for i = 1:numel(S)
newS(i) = structfun(@(x) x(3:end-2),S(i),'UniformOutput',false)
end

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by