How to filter a cell array filled with strings?
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Dear all,
I have a dataset with 576 cells [1x576] and all cells contain strings [1x1 struct]. These strings contain two colums (field, value), e. g.:
A01 = struct('a',1,'b',2,'c',0)
A02 = struct('a',0,'b',2,'c',1)
A03 = struct('a',2,'b',2,'c',0)
A04 = struct('a',0,'b',1,'c',1)
A05 = struct('a',1,'b',0,'c',2)
A = {A01,A02,A03,A04,A05}
How can I filter all cells with a specific field name and extract them (as example: how can I filter all structs with a=1 and save the b values in new array)?
Sincerely yours, Max
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Stephen23
2024-4-12
编辑:Stephen23
2024-4-12
Storing lots of scalar structures in a cell array is inefficient data design, which leads to inefficient code.
Assuming that all of the scalar structures have the samew fields (as your example shows), then much better data design would be to use one non-scalar structure array:
A = struct('a',{1,0,2,0,1},'b',{2,2,2,1,0},'c',{0,1,0,1,2})
This has more efficient memory and access, as well as offering some convenient syntaxes for accessing the data:
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Adam Danz
2019-12-4
编辑:Adam Danz
2019-12-6
This will return a logical array the same size as 'A' where TRUE values indicate elements of A that meet the following requirements:
- A{i} is a structure
- A{i} contains a field named 'a'
- The value of field 'a' is equal to 1
keyField = 'a';
keyValue = 1;
idx = cellfun(@(s)isstruct(s) && any(strcmp(fieldnames(s),keyField)) && isequal(s.(keyField),keyValue), A)
To filter those structures from the cell array A,
A(idx)
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