Short Question about Multiple cases in for end

Question

Fahmy Shandy 2019-12-7

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回答： dpb 2019-12-7

I want to make multiple commands in "for loop" like this

for j=1:10 && k=0:9 && m=1:11 && n=1:1
    x(j)^k + m -2*n
end

But it's not work. It's not my real question actually (because my script is too long to write). I just simplify my question a bit with different approach. What is the correct script?

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Answer 1

dpb 2019-12-7

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Depends upon what you mean to do...if want each combination of the four variables, then you write a set of nested for loops...

for j=1:10
  for k=0:9
    for m=1:11
      for n==1:1
        y=x(j)^k + m - 2*n;
      end
    end
  end
end

Of course, for n=1:1 is superfluous; one simply defines n outside the loops for a constant value; one presumes that's not the real case. That leaves one with 10*10*11*1 calculations of y; the allocation of a place to store the results isn't shown above.

ndgrid may be of interest...