Converting a cell array into a matrix of stipulated number of columns and rows

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Consider I have a cell array containing 4 cells
Each cell containd 'n' elements
Now I want to covert it into an array of size "n*4" where element of each row is take from elements of each cell
If it has tto be more clear for eg: ist row of the matrix contains 4 elements - each element is picked from 1st element of each cell.
I have used the model
for i = 1:numel(W{1})%w is the cell
wid(i,:)=double(cellfun(@(v) v(i),W));
end
But it is taking more time in matlab.So, is there any best and simple solution for this problem which can be simulated in less time?

采纳的回答

Andrei Bobrov
Andrei Bobrov 2019-12-12
编辑:Andrei Bobrov 2019-12-12
Let C - your cell array.
if cells sizes are the same:
out = reshape(cat(2,C{:}),[],4);
if not the same:
out = cell2mat(cellfun(@(x)x(:),C,'un',0));

更多回答(1 个)

meghannmarie
meghannmarie 2019-12-12
wid = [W{1}(:) W{2}(:) W{3}(:) W{4}(:)];

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