Too many output arguments.

Question

Paul Rogers 2019-12-16

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/496971-too-many-output-arguments

编辑： per isakson 2019-12-18

采纳的回答： per isakson

在 MATLAB Online 中打开

I've found this code that may help me a lot.

I cannot run, it keeps saying:

Error using type
Too many output arguments.

my version is 2014b

the code is

function [t,y]=valori(type)
a=340;
S=0.25;
x10=0.85;
U=144;
if (type == 1)
    
    Ac=0.0034;
    Vp=0.32;
    Lc=0.3;
    H=3.2613e4;
    W=0.3689;
    
else
    
    if (type == 2)
        
        Ac=0.0033;
        Vp=0.025;
        Lc=1.22;
        H=0.09e5;
        W=0.1;
    
    else
        
        Ac=0.0090;
        Vp=0.001;
        Lc=2.8;
        H=1.55e4;
        W=0.1587;
    
    end
    
end
[t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S);
end
function [t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S)
wh=a*sqrt(Ac/(Vp*Lc));  
B=U/(2*wh*Lc);  
k=x10-S*(x10-(1/3)*(x10.^3));   
[t,y]=ode45(@(t,y)greitzer10(H,W,B,U,Ac,y,S,k),[0 100],[0,0]);
subplot(2,2,1)
plot(t,y(:,1))
xlabel('t')
ylabel('\phi_c')
subplot(2,2,2)
plot(y(:,1),y(:,2))
xlabel('\phi_c')
ylabel('\psi')
subplot(2,2,3)
plot(t,y(:,2))
xlabel('t')
ylabel('\psi')
end
function dydt = greitzer10(H,W,B,U,Ac,y,S,k)
dydt = [ ((3*H*Ac*B)/(W*U))*((y(1)-(1/3)*((y(1).^3)))-y(2)); ((W*U)/(3*H*Ac*B))*(y(1)-(S*y(2)+k)) ];
end

this might be a missing part:

function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));

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Answer 1

per isakson 2019-12-17

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/496971-too-many-output-arguments#answer_406664

编辑：per isakson 2019-12-17

在 MATLAB Online 中打开

I fail to reproduce the error you report

>> [t,y] = valori( 2 );
>> [t,y] = valori( 1 );
>> [t,y] = valori( 3 );

no error, no warning and produces a figure with three diagrams.

However

>> [t,y] = valori( type );
Error using type
Too many output arguments. 
>> 

"type" is the name of a function that doesn't return any output. Try

>> type=1; [t,y] = valori( type );

That works, but now you'll get unexpexted results if you try to use the function, type

Conclusion: Avoid to use function names as names of variables.

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Paul Rogers 2019-12-17

在 MATLAB Online 中打开

function [t,y]=valori(type)
a=340;
S=0.25;
x10=0.85;
U=144;
if (type == 1)
    
    Ac=0.0034;
    Vp=0.32;
    Lc=0.3;
    H=3.2613e4;
    W=0.3689;
    
else
    
    if (type == 2)
        
        Ac=0.0033;
        Vp=0.025;
        Lc=1.22;
        H=0.09e5;
        W=0.1;
    
    else
        
        Ac=0.0090;
        Vp=0.001;
        Lc=2.8;
        H=1.55e4;
        W=0.1587;
    
    end
    
end
[t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S);
end
function [t,y]=greitzer2(a,Ac,Vp,Lc,U,H,W,x10,S)
wh=a*sqrt(Ac/(Vp*Lc));  
B=U/(2*wh*Lc);  
k=x10-S*(x10-(1/3)*(x10.^3));   
[t,y]=ode45(@(t,y)greitzer10(H,W,B,U,Ac,y,S,k),[0 100],[0,0]);
subplot(2,2,1)
plot(t,y(:,1))
xlabel('t')
ylabel('\phi_c')
subplot(2,2,2)
plot(y(:,1),y(:,2))
xlabel('\phi_c')
ylabel('\psi')
subplot(2,2,3)
plot(t,y(:,2))
xlabel('t')
ylabel('\psi')
end
function dydt = greitzer10(H,W,B,U,Ac,y,S,k)
dydt = [ ((3*H*Ac*B)/(W*U))*((y(1)-(1/3)*((y(1).^3)))-y(2)); ((W*U)/(3*H*Ac*B))*(y(1)-(S*y(2)+k)) ];
end
function y=carcomp(C0,H,x,W)
y=C0+H*(1+(3/2)*((x/W)-1)-(1/2)*(((x/W)-1).^3));
end
C0 = 0;     % or a better value
cc = carcomp( C0, H, t, W );
subplot(2,2,4)
plot( t, cc )
xlabel('t')
ylabel('carcomp')

then i type in the command

type=1; [t,y] = valori( type );

but it says this:

Error: File: valori.m Line: 63 Column: 1

This statement is not inside any function.

(It follows the END that terminates the definition of the function "carcomp".)

per isakson 2019-12-18

编辑：per isakson 2019-12-18

"This statement is not inside any function." Why did you put it at the end of the file?

Read up on function and Local Functions

Here is a screen clip of the end of your file valori.m

Comments

Upper left corner. With an indention of 4, I find it easier to see the scope of the functions.
Upper right corner. The red box shows that the Code Analyzer has spotted a syntax error. Try to understand and fix that problem before running the code. See Check Code with the Code Analyzer
The arrow points at the the end of the function valori.