plotting a simple Graph
2 次查看(过去 30 天)
显示 更早的评论
Hi everyone,
Trying to plot a graph unsucssesfully :((
alpha=2.2;
Mx0=34.8262;
My0=15.7563;
Mx=linspace(0,50,0.0001);
Interaction_Curve=(Mx./Mx0).^alpha+(My./My0).^alpha-1
plot(Interaction_Curve,Mx)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/257069/image.jpeg)
Thank You Very much
2 个评论
采纳的回答
Star Strider
2019-12-24
One problem is that ‘My’ is missing. Beyond that, the linspace arguments resulted in an empty vector for ‘Mx’.
It might be easier to plot this as an implicit function:
alpha=2.2;
Mx0=34.8262;
My0=15.7563;
Interaction_Function = @(Mx,My) (Mx./Mx0).^alpha+(My./My0).^alpha-1;
figure
fimplicit(Interaction_Function, [0 50 0 30])
ylim([0 30])
producing:
![1plotting a simple Graph - 2019 12 24.png](https://www.mathworks.com/matlabcentral/answers/uploaded_files/257078/1plotting%20a%20simple%20Graph%20-%202019%2012%2024.png)
That seems to produce the sort of plot you want. Make appropriate changes to the second agrument in the fimplicit call to get the result you want.
9 个评论
更多回答(1 个)
Image Analyst
2019-12-24
Try this:
alpha = 2.2;
Mx0 = 34.8262;
My0 = 15.7563;
Mx = linspace(0,50, 1000);
My = linspace(0,50, 1000); % Not sure what My should be!!!
Interaction_Curve = (Mx./Mx0).^alpha+(My./My0).^alpha-1
plot(Mx, Interaction_Curve, 'b-', 'LineWidth', 2)
grid on;
Be sure to define My because I just guessed incorrectly.
2 个评论
Image Analyst
2019-12-24
I know. Because I don't have the value of the My variable. That's why I asked you to define it. What is it? But doesn't matter since it looks like Star figured it out.
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!