App designer: randomly generated sentence GUI

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Hello everyone,
I have created a random phrase generator in Matlab; it starts by choosing between two types of sentences (using randi) and then uses randi again to construct one of the two types and displays it in the command window.
I am having, however, hell of a time trying to create a GUI that displays the generated text somewhere. I added a callback to my random phrase generator function and associated it with a button and a textbox; the function runs properly when I press the button but nothing appears in the textbox.
Anyone knows?
I have been looking it up but it seems that the app designer has been changing every year.
  2 个评论
Mohammad Sami
Mohammad Sami 2019-12-26
Can you provide a copy your callback function to see if anything is wrong with it.
Eleanna Kritikaki
Eleanna Kritikaki 2019-12-26
编辑:Stephen23 2019-12-26
Yes, here it is below. Thing is i am not sure exactly where to copy and paste it and what I should modify etc, what to tie to what... I guess the button and the text box have to share the same callback etc.
% Random phrase generator
clear all;
clc;
% Choose between the two types
rng('shuffle')
Ch=randi(35);
if Ch==10
rng('shuffle')
Type_1 = {'phrase 1', 'phrase 2',.... 'phrase n'};
Nugget = [Type_1{randi(numel(Type_1))}];
fprintf(Nugget)
elseif Ch~=10
% Create 3 types of cells to put them in a cell array
Start = {'phrase 1 ','phrase 2 ','phrase 3 '...'phrase n'};
Middle = {'phrase 1 ','phrase 2 ','phrase 3 '...'phrase n'};
Final={'phrase 1 ','phrase 2','phrase 3 '...'phrase n '};
% Put them all in a cell array
A={Start,Middle,Final};
% Create variable with a combination of the three parts called 'Sentence'
rng('shuffle');
a=Start{randi(numel(Start))};
rng('shuffle');
b=Middle{randi(numel(Middle))};
rng('shuffle');
c=[Final{randi(numel(Final))} '.'];
Sentence = [a b c];
% Print this variable
fprintf(Sentence)
end

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采纳的回答

Mohammad Sami
Mohammad Sami 2019-12-26
If you are using app designer, to build your GUI you can do as follows.
Drag and drop a button and an "Edit Field (Text)" into your app.
If this is a blank app, the names would be Button and EditField.
Right click the button, goto callbacks and select Add ButtonPushedFcn callback.
The designer will switch to code view.
You can then simply put in your random generation code in the callback.
At the end just assign the Sentence output to the EditField as follows
function ButtonPushed(app, event)
% Your random sentence generator code here
% Sentence = ....
app.EditField.Value = Sentence;
end
This should update the edit field with a new sentence everytime you click the button.
  3 个评论
Image Analyst
Image Analyst 2019-12-26
What is the name of your edit text box? Is it EditField? It's case sensitive so check that also.
Eleanna Kritikaki
Eleanna Kritikaki 2019-12-27
So thanks Mohammad, this finally worked. However, as Image Analyst pointed out below, the 'clear all' command had to go.

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更多回答(1 个)

Image Analyst
Image Analyst 2019-12-26
编辑:Image Analyst 2019-12-26
Assuming your edit text box is named edtText, try this. First create your sentence however you do it, then:
app.edtText.String = yourSentence; % Set string property, not value property.
Also, your callback for the push button where you create this sentence and send it to the GUI should not have a "clear all" command in it.
  4 个评论
Eleanna Kritikaki
Eleanna Kritikaki 2019-12-27
Hello!
I did try both- capital s as well as lower case s, and got the same message (I guess I erroneously copied and pasted the latter one). Apologies!
Mohammad Sami
Mohammad Sami 2019-12-30
Good to hear that it works.
I did not notice the clear all.
The reason why it broke your code, is that it will clear the variables passed into your function (app and event). So you will no longer be able to access these variables in the later part of your function. In this case we needed the "app" variable to access the edit text field.

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