Problem using the FIND function to identify the position of a negative decimal number.

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Stanislao Pinzón
Stanislao Pinzón 2019-12-28
回答： Image Analyst 2019-12-28
Hello.
I need to find the position of a negative decimal number in a vector. The code I've used is as follows:
a = -2:0.05:0;
num = -0.95;
position = find(a==-0.95);
The problem is with some numbers like the one set in num. Although the number exists within the a vector, the result I get is:
1-0 empty double row vector
What could be the problem? and how can I fix it?. Thanks.
Best regards

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Matt J
Matt J 2019-12-28
编辑：Matt J 2019-12-28
The numbers you are comparing differ by small floating point errors,
>> a(22)-(-0.95)
ans =
-1.1102e-16
Use ismembertol, instead.
>> [~,position]=ismembertol(num,a)
position =
22

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Image Analyst
Image Analyst 2019-12-28

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