Time averaged values for each 100 iteration

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m m
m m 2020-1-1
编辑： Matt J 2020-1-1
i want to calculate the time averged value for each 100 iteration. knowing that my program is like this :
for m = 1:20000 %time iteration
for k = 1:1000
X(k)=
end(k)
if m>10000
%here i want to calculate the aceraged valu of X but for each 100 itaetation (m) i want to store the Xaveraged
for k = 1:1000
Xaveraged(k)=Xaveraged(k) + X(k)
end
end
end(m)

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回答（2 个）

Matt J
Matt J 2020-1-1
编辑：Matt J 2020-1-1
Xaveraged=mean(reshape(X,100,[]));
  1 个评论
m m
m m 2020-1-1
thank you Matt for your rely.
but i dont intersttand Xaveraged=mean(reshape(X,100,[])); because Xaveraged depends on K, i want for each 100 m iteration store the values of Xaveraged in each K.

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Matt J
Matt J 2020-1-1
编辑：Matt J 2020-1-1
Maybe this is what you want.
X=nan(1000,20000); %pre-allocate
for m = 1:20000 %time iteration
for k = 1:1000
X(k,m)=... %store for all k and m
end
end
%compute after iterations all finished
Xaveraged=squeeze( mean(reshape(X,1000,100,[]),2) );
  1 个评论
Matt J
Matt J 2020-1-1
编辑：Matt J 2020-1-1
Or, if you want to be more conservative with memory (but why??), then a variation is
X=nan(1000,100); %pre-allocate
Xaveraged=nan(1000,200); %pre-allocate
for s=1:200
for t=1:100
m=s*t; % time iteration number
for k = 1:1000
X(k,t)=...
end
end
Xaveraged(:,s)=mean(X,2);
end

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