how to plot this velocity profile...i have solved equation by laplace transform.equqtion in terms of exponentian and complementary error function...have tried and defined functions but output was blank...pls help me out

1 次查看(过去 30 天)
close all
syms z;
gr=2;
gc=2;
M=1;
w=0.5;
pr=7;
sc=2.01;
t=0.4;
m=(M+(2*1i*w));
s1=z;
s2=(2*sqrt(t));
x=((s1)./(s2));
a1=(x*t);
a2=(2*m*(sqrt(pi)));
a=((m)./(pr-1));
b=((m)./(sc-1));
x=((s1)./(s2));
u1=((x^2+(m*t))*t);
u2=4*m;
d1=(x*(sqrt(t)))*(1-4*m*t);
d2=(8*m^3/2);
v1=gr;
v2=(a*(1-pr));
k1=gc;
k2=(b*(1-sc));
h1=exp(a*t);
h2=2;
e1=(exp(2*x*(sqrt(m*t))));
e2=(erfc(x+(sqrt(m*t))));
e3=(exp(-2*x*(sqrt(m*t))));
e4=(erfc(x-(sqrt(m*t))));
b1=(exp(2*x*((sqrt((m+a)*t)))));
b2=(erfc(x+(sqrt((m+a)*t))));
b3=(exp(-2*x*(sqrt((m+a)*t))));
b4=(erfc(x-(sqrt((m+a)*t))));
e5=exp(-(x^2+(m*t)));
c1=(exp(2*x*(sqrt(pr*a*t))));
c2=(erfc(x*(sqrt(pr)+(sqrt(a*t)))));
c3=((exp(-2*x*(sqrt(pr*a*t)))));
c4=(erfc(x*(sqrt(pr)-(sqrt(a*t)))));
l1=(exp(2*x*(sqrt(sc*b*t))));
l2=(erfc(x*(sqrt(sc)+(sqrt(b*t)))));
l3=((exp(-2*x*(sqrt(sc*b*t)))));
l4=(erfc(x*(sqrt(sc)-(sqrt(b*t)))));
f1=(exp(b*t));
f2=2;
l=((a1)./(a2));
f=((f1)./(f2));
h=((h1)./(h2));
j1=((u1)./(u2));
j2=((d1)./(d2));
j3=((v1)./(v2));
j4=((k1)./(k2));
q1=(2*(j1*((e1*e2)+(e3*e4))+(j2*((e3*e4)-(e1*e2))-(l*e5))));
q2=((j3+j4)*(1/2)*((e1*e2)+(e3*e4)));
q3=((j3*(h*(b1*b2)+(b3*b4))));
q4=((j4*(f*(b1*b2)+(b3*b4))));
q5=(j3*(erfc(x*sqrt(pr))));
q6=(j4*erfc(x*sqrt(sc)));
q7=(j3*(h*((c1*c2)+(c3*c4))));
q8=(j4*(f*((l1*l2)+(l3*l4))));
q=(q1+q2-q3-q4-q5-q6+q7+q8);
fplot(z,q);
xlim([0 5])
ylim([0 1])
title('Axial velocity profiles for different values of gr & gc');
  6 个评论

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Partial Differential Equation Toolbox 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by